Copy all but some properties of an object in ES6

Since I started playing with ES6 about half a year ago I really came to love the new syntax, as it provides a much more python-ish feel to Javascript development.

One of the functions I like the most is the awesome Object.assign().

You can use it for all sorts of things:

const oldObject = { foo: 'bar', baz: 42 };
// (shallow) copy an object
const newObject = Object.assign({}, oldObject);
// overwrite some values
const overwritten = Object.assign({}, oldObject, { foo: 'fighters' });
// overwritten is { foo: 'fighters', baz: 42 }
// merge objects
const other = { luftballons: 99 };
const merged = Object.assign({}, oldObject, other);
// merged is { foo: 'bar', baz: 42, luftballons: 99 }

and more awesomeness that you can find, as always, on the MDN site.

One thing that I found out today that made my day better is that you can use Object.assign() to copy an object except for some of its properties.

const oldObject = { foo: 'bar', baz: 42 };
let noFoo = Object.assign({}, oldObject, { foo: undefined });
// noFoo is { foo: undefined, baz: 42 }
// this call is also equivalent to this
noFoo = { ...oldObject, foo: undefined };

[Edit – July 2019]: if you iterate through your items and check/filter for truthiness, this might be enough. However, if you can target ES2018, there’s a new syntax that actually removes the key as well:

const oldObject = { foo: 'bar', baz: 42 };
const { foo, ...noFoo } = oldObject
// now noFoo is { baz: 42 }

See this post about the rest/spread operator in ES2018

As easy as that!

I find myself doing this kind of operation quite often, namely when I decorate some object generated from JSON retrieved from a server and want to send it back after changing it client-side. This syntax makes it oh-so-simple!


4 thoughts on “Copy all but some properties of an object in ES6

Leave a Reply

Fill in your details below or click an icon to log in: Logo

You are commenting using your account. Log Out /  Change )

Google photo

You are commenting using your Google account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s